7x^2+560=1120

Solution for 7x^2+560=1120 equation:

7x^2+560=1120

We move all terms to the left:

7x^2+560-(1120)=0

We add all the numbers together, and all the variables

7x^2-560=0

a = 7; b = 0; c = -560;
Δ = b2-4ac
Δ = 02-4·7·(-560)
Δ = 15680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15680}=\sqrt{3136*5}=\sqrt{3136}*\sqrt{5}=56\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56\sqrt{5}}{2*7}=\frac{0-56\sqrt{5}}{14}
=-\frac{56\sqrt{5}}{14}
=-4\sqrt{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56\sqrt{5}}{2*7}=\frac{0+56\sqrt{5}}{14}
=\frac{56\sqrt{5}}{14}
=4\sqrt{5}
$